A1.543 gram sample containing sulfate ion was treated with barium chloride reagent, and 0.2243 grams of barium sulfate was isolated. calculate the percentage of sulfate ion in the sample.

The mass percent of sulfate ion in the sample is 5.98 %

Explanation:

We are given:

Mass of barium sulfate = 0.2243 g

We know that:

Molar mass of barium sulfate = 233.4 g/mol

Molar mass of sulfate = 96.06 g/mol

To calculate the mass of sulfate ion present in given amount of barium sulfate, we use unitary method:

In 233.4 g of barium sulfate, the mass of sulfate ion present is 96.06 g

So, in 0.2243 g of barium sulfate, the mass of sulfate ion present will be =

To calculate mass of sulfate ion present in the sample, we use the equation:

Mass of sulfate ion = 0.0923 g

Mass of sample = 1.543 g

Putting values in above equation, we get:

Hence, the mass percent of sulfate ion in the sample is 5.98 %

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explanation: