Gef3h is formed from geh4 and gef4 in the combination reaction: geh4 + 3gef4 -> 4gef3h. if the reactiln yield is 92.6%, how many moles of gef4 are needed to produce 8 mol of gef3h?

Answer : The number of moles of needed to produce 8 mole of are, 6.48 moles.

Explanation :

The given balanced chemical reaction is:

First we have to calculate the moles of

From the balanced chemical reaction we conclude that,

As, 4 moles of produced from 3 mole of

So, 8 moles of produced from mole of

Now we have to calculate the moles of when the reaction yield is 92.6 %.

As, 92.6 % yield produced from 6 moles of

So, 100 % yield produced from moles of

Therefore, the number of moles of needed to produce 8 mole of are, 6.48 moles.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole