Amixture of potassium bromide and potassium hydroxide has a total mass of 5.50 g. if the mixture contains 2.45 g k, what is the mass in grams of potassium hydroxide in the mixture? give the numerical part of your answer only; don't include the units.

1.72 grams is the mass of potassium hydroxide in the mixture.

Explanation:

Total mass of the mixture = M = 5.50 g

Le the mass of KBr and KOH be x and y.

x + y = 5.50 g..[1]

Moles of KBr =

1 mol of KBr has 1 mol of potassium . Then moles of KBr will have:

Mass of potassium in x amount of KBr :

= ...[2]

Moles of KOH=

1 mol of KOH has 1 mol of potassium . Then moles of KOH will have:

Mass of potassium in y amount of KOH :

= ...[3]

Mass of potassium in the mixture = 2.45 g

0.33x+ 0.70y=2.45 g..[4] (from [2] and [3] )

On solving [1] and [4] we get:

x = 3.78 g, y = 1.72 g

1.72 grams is the mass of potassium hydroxide in the mixture.