Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kj of heat. the bomb calorimeter has a mass of 1.20 kg and a specific heat of 3.55 j/(gi°c). if the initial temperature of the calorimeter is 22.5°c, what is its final temperature?

The final temperature of the calorimeter is 25.8 °C

From the question given above, the following data were obtained:

Q = MC(T₂ – T₁)

14000 = 1200 × 3.55(T₂ – 22.5)

14000 = 4260(T₂ – 22.5)

Clear bracket

14000 = 4260T₂ – 95850

Collect like terms

14000 + 95850 = 4260T₂

109850 = 4260T₂

Divide both side by 4260

T₂ = 109850 / 4260

T₂ = 25.8 °C

Learn more about heat transfer:

link

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.