Commercial grade hcl solutions are typically 39.0% (by mass) hcl in water. determine the molarity of the hcl, if the solution has a density of 1.20 g/ml.

12.82 mol/L the molarity of the HCl.

Explanation:

Suppose in 100 grams of 39.0% (by mass) HCl in water.

Volume of solution = V

Density of the solution = d = 1.20 g/mL

Mass = Density × Volume

Mass of HCl = 39.0% of 100 grams=

Moles of HCl =

The molarity of the HCl = M

12.82 mol/L the molarity of the HCl.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

2b2t

explanation:

2b2t