Kcl(aq) + agf(aq) → agcl(s) + kf(aq) if 0.25 moles of potassium chloride are consumed completely, how many moles of potassium fluoride will be produced? a) 1.0 mole b) 0.25 moles eliminate c) 0.50 moles d) there is no way to tell because we do not have enough information

option B) 0.25 moles KF

Explanation:

1) The coefficients of the balanced chemical equation tells you the mole ratios of every reactant and every product

KCl(aq) + AgF(aq) → AgCl(s) + KF(aq)

From that the ratios are:

1 mol KCl : 1 mol AgF : 1 mol AgCl : 1 mol Kf

2) with those mole ratios and the number of moles of any of the species, you can set a proportion to determine the desired unkwoun value.

In tis case, that is not necessary because the ratio is 1 : 1: 1 : 1,which means that the number of moles of any product is the same number of moles consumed of any reactant.

3) Since 0.25 moles of KCl are consumed, you know that 0.25 moles of AgCl and 0.25 moles of KF are produced.

Then, the answer is that 0.25 moles of KF are produced.

The formula is (nh4)2co3