For the reaction bro3- + 5br- + 6h+ → 3br2 + 3h2o at a particular time, -δ [bro3-]/δt = 1.5 × 10-2 m/s. what is -δ [br-]/δt at the same instant?

7.5 M/s

Explanation:

The equation of Reaction is given as;

BrO^3- + 5Br^- + 6H^+ > 3Br2 + 3H2O. (1)

Rate of Reaction is the speed in which reaction take place for the transformation of reactants to products.

For the reaction (1) above;

===> - (∆[BrO^3-]/ ∆t) = -(∆Br^-])/∆t = -∆[H^+] /∆t = ∆[Br2]/∆t.

Notice from above that there is negative signs at the Change in the reacti species. This is so, because the Reactants is been used up in the reaction to produce the products

NB : I did not raise the number of the moles to the power of each species to avoid clumsiness.

We are given that; - (∆[BrO^3-]/ ∆t) = 1.5 × 10^-2 m/s; -(∆Br^-])/∆t = x m/s.

1 mole of BrO3^- = 5 mole of Br^-

So, 5 × 1.5 ×10^-2 .

= 7.5 × 10 ^-2 M/s

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.