How many moles are in 226 g of fe(no2)2 ?

By getting the molar mass of Fe (NO2)2 = 55.85 + ((14+16*2))*2 = 147.85 g/mol

and we have the mass weight of Fe(NO2)2 = 226 g
SO we can get the no.of moles of Fe(NO2)2 from this formula:

∴ n= mass weight / molar mass
   = 226 / 147.85 = 1.53 mol

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