What volume of a 2.5 m stock solution of acetic acid (hc2h3o2) is required to prepare 100.0 milliliters of a 0.50 m acetic acid solution? use the equation mconcentrated × vconcentrated = mdilute × vdilute. 90points given to correct answer

Answer is: volume is 20 mL.
c₁(CH₃COOH) = 2,5 M.
c₂(CH₃COOH) = 0,5 M.
V₂(CH₃COOH) = 100 mL.
V₁(CH₃COOH) = ?
c₁(CH₃COOH) · V₁(CH₃COOH) = c₂(CH₃COOH) · V₂(CH₃COOH).
2,5 M · V₁(CH₃COOH) = 0,5 M · 100 mL.
V₁(CH₃COOH) = 0,5 M · 100 mL ÷ 2,5 M.
V₁(CH₃COOH) = 20 mL ÷ 1000 mL/L =0,02 L.

i think it is d. e because the next one is igneous.

the answer is:  

line graphs show patterns in data with variables that change over time; whereas, circle graphs show data as parts out of a whole (such as out of 100%).