Shown below is a lewis structure of the formamidinium ion. what geometry is exhibited by the two nitrogens in the formamidinium ion?

The formamidinium ion structure is shown below.

A: trigonal planar

B: trigonal pyramidal

Explanation:

In the formamidinium ion, there are two nitrogen atoms, which are represented below by A and B. The geometry of a molecule is determined by the VSEPR theory, which states that the bonded electrons and the lone pairs of electrons intended to repulse to form a more stable compound.

Nitrogen has 5 electrons in its valence shell, so n the nitrogen A, there are 3 bonds (1 double bond and 2 simple bonds), and there are no lone pairs in the nitrogen atom (the central atom), thus the repulsive forces will be only by the bonds, and the geometry will be trigonal planar.

In nitrogen B, there are 3 simple bonds and one lone pair, which contributes to the repulsive forces, thus, the geometry must be trigonal pyramidal.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.