Zinc metal reacts with hydrochloric acid to produce hydrogen gas and an aqueous solution of zinc(ii) chloride. what is the reducing agent in this reaction? maybe prof. umbridge was right in trying to remove her.

zinc is the reducing agent.

Explanation:

1) Reducing agent is the agent that releases electrons, is oxidized (its oxidation number increases)   and causes the reduction of the other agent (the reduced spices reduces its oxidation state).

2) Chemical equation:

Zn(s) + HCl (aq) → H2(g) + ZnCl2(s)

3) determine the oxidation states of each spices

Zn (s): oxidation state = 0
Zn in ZnCls: oxidation state = + 2.

Therfore Zn was oxidized and is the reducing agen.

H in HCl: oxidtation state = +1

H in H2: oxidation state = 0

Therefore H2 was reduced (it is the oxidizing agent).

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.