Which equation represents the reduction half-reaction for this redox equation? mg + cuso4 mgso4 + cu a. cu cu b. cu + 2e- cu c. cu cu + 2e- d. cu + 3e- cu,

The oxidation number of Cu in CuSO₄ is +2 and 0 in Cu, the free elemental form. As the oxidation of Cu decreases from +2 to 0, we are looking at the reduction half-reaction for the given redox reaction:

Cu²⁺ + 2e⁻ → Cu

The correct answer is option B.

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.