To increase the solubility of a gas at constant temperature from 1.20 g/l, at 1.4 atm, to 2.3 g/l, the pressure would have to be increased to 2.7 atm 0.7 atm 0.37 atm 1.37 atm

Answer : The pressure of the gas would be, 2.7 atm

Explanation:

According top the Henry's Law, the solubility of a gas in a liquid is directly proportional to the pressure of the gas.

or,

where,

= initial solubility of gas = 1.20 g/L

= final solubility of gas = 2.3 g/L

= initial pressure of gas = 1.4 am

= final pressure of gas = ?

Now put all the given values in the above formula, we get the final pressure  of the gas.

Therefore, the pressure of the gas would be, 2.7 atm

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