Consider the following equilibrium: 4ko2(s) + 2h2o(g) 4koh(s) + 3o2(g) which of the following is a correct equilibrium expression? keq=[koh]4[o2]3[ko2]4[h2o]2 keq=[h2o]2[o2]3 keq=[ko2]4[h2o]2[koh]4[o2]3 keq=[o2]3[h2o]2

Explanation:

The equilibrium constant (Keq) is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. In Keq we include gases and aqueous species, but not solids nor pure liquids because their concentration remains almost constant over time.

Let's consider the following reaction.

4 KO₂(s) + 2 H₂O(g) ⇄ 4 KOH(s) + 3 O₂(g)

Then, the equilibrium constant is:

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so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer