Chemistry, 29.07.2019 07:00 emmahirstein

Arrange the objects in order from least to greatest potential energy. assume that gravity is constant. (use pe = m × g × h.) tiles a 15-kilogram stone found at a height of 3 meters10 kilograms of water stored at a height of 9 metersa 1-kilogram ball located 20 meters in the aira box of books weighing 25 kilograms placed on a shelf 2 meters high

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Answer from: micahmereus100

Answer : The order of potential energy from least to greatest is,

(3) < (1) < (4) < (2)

Explanation :

Formula used :

$P.E=m\times g\times h$

where,

P.E = potential energy

m = mass of an object

g = gravity constant = 9.8m/s^2

h = height

Now we have to calculate the potential energy of following options.

(1) Tiles a 15-kilogram stone found at a height of 3 meters.

$P.E=15Kg\times 9.8m/s^2\times 3m=441J$

(2) 10 kilograms of water stored at a height of 9 meters.

$P.E=10Kg\times 9.8m/s^2\times 9m=882J$

(3) 1-kilogram ball located 20 meters.

$P.E=1Kg\times 9.8m/s^2\times 20m=196J$

(4) In the area box of books weighing 25 kilograms placed on a shelf 2 meters high.

$P.E=25Kg\times 9.8m/s^2\times 2m=490J$

From this we conclude that, the order of potential energy from least to greatest is,

(3) < (1) < (4) < (2)

Answer from: quinteroalex2001

The objects in order from least to greatest potential energy:

Ball < Stone < book < Water

Explanation:

Potential energy is an energy of the body due to its position.

P.E=mgh

m = mas of the body

g = Acceleration due to gravity

h = Height at which body is placed

Potential energy of the stone:

m = 15 kg, h = 3 m , g = 9.8 m/s^2

$P.E_1=15 kg\times 9.8 m/s^2\times 3 m=441 J$

Potential energy of the water:

m = 10 kg, h = 9 m , g = 9.8 m/s^2

$P.E_2=10 kg\times 9.8 m/s^2\times 9 m=882 J$

Potential energy of the ball :

m = 1 kg, h = 20 m , g = 9.8 m/s^2

$P.E_3=1 kg\times 9.8 m/s^2\times 20 m=196 J$

Potential energy of the book :

m = 25 kg, h = 2 m , g = 9.8 m/s^2

$P.E_4=25 kg\times 9.8 m/s^2\times 2 m=490 J$

The potential energies in order from least to greatest :

P.E_3

The objects in order from least to greatest potential energy:

Ball < Stone < book < Water

Answer from: Quest

answer : (a) volume of the gas = 8.67 × $10^{-3}$ l

(b) second virial coefficient b = -1.21226 l/mole

solution : given, t = 300k

p = 20atm

z = 0.86

n = 8.2 mmoles = 8.2 × $10^{-3}$ moles

r = 0.082 l atm/k/mol

find, (a) volume of gas and (b) second virial coefficient b at 300k.

formula used : $z=\frac{pv}{nrt}$

and $z=1+\frac{b}{v}$

(a) $z=\frac{pv}{nrt}$

$v=\frac{znrt}{p}$

= $\frac{0.86\times 8.2\times[tex]10^{-3}$ \times 0.082\times 300}{20}[/tex]

= 8.67 × $10^{-3}$ l

(b) $z=1+\frac{b}{v}$

$b=(z-1)v$

= (0.00867-1) × 8.659

= - 8.5839 l/mole

Answer from: Quest

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