How much heat is lost when 350g of iron cools from 54.1 to 22.4oc? (the specific heat of iron is 0.450 j/g oc)

Heat lost = mcΔT, where m is the mass of iron , c is the specific heat capacity of iron, and ΔT is the change in temperature.
Mass of iron = 350 g, specific heat capacity = 0.450 J/gC while;
change in temperature = 54.1 - 22.4 = 31.7 
Hence; heat = 350 × 0.450 × 31.7
                    = 4992.75 J or 4.993 kJ