How many times greater is the rate of effusion of molecular fluorine than that of molecular bromine at the same temperature and pressure?

The rate of diffusion of fluorine is 2.05 times to that of bromine.

Explanation:

To calculate the rate of effusion of gas, we use Graham's Law.

This law states that the rate of effusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:

Molar mass of bromine =  160 g/mol

Molar mass of fluorine = 38 g/mol

For the rate of effusion of bromine to fluorine  we write the expression:

Hence, the rate of diffusion of fluorine is 2.05 times to that of bromine.

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