What is the molarity of a naoh solution if 28.2 ml of a 0.355 m h2so4 solution is required to neutralize a 25.0-ml sample of the naoh solution? what is the molarity of a naoh solution if 28.2 ml of a 0.355 m h2so4 solution is required to neutralize a 25.0-ml sample of the naoh solution? 0.8011250.3150.6290.400?

The  molarity  of  NaOH  solution  is  calculated  as   follows
step  one ;calculate  the  number  of  moles  of  H2SO4

moles  of  H2SO4=  molarity  x  volume/1000
                             =28.2   x0.355/1000=  0.01  moles  of  H2SO4

2NaOH  +H2SO4  >Na2SO4  +2H2O
from  the    equation   above  the   ratio  of  NaOH  to  H2SO4  is  2:1  therefore  the  moles  of   NaOH  is  =  2  x  0.01=0.02  moles

molarity  of   NaOH=  moles  of  NaOh/volume  x  1000

that  is  0.02/25   x1000=  0.8 M

Only one reactant yields 2 or more products. meaning you will only have 1 product and it will break down into 2 or more products. eg. h2o -> h2 + o2