Write the complete balanced equation for the following reaction: (3 points) ch3ch2oh + o2 yields co2 + h2o

  CH3CH2OH + O2 → CO2 + H2O 
The reaction above is combustion of a compound with C, H, and O. 
The following method will balance any combustion equation of CxHyOz. 

1st balance the C’s 
2 C’s on left, 2 C’s on right. Make 2 C’s on right, by making 2 CO2’s on right. 

CH3CH2OH + O2 → 2 CO2 + H2O 

2nd balance the H’s 
6 H’s on left, 2 H’s on right. Make 6 H’s on right, by making 3 H2O’s on right. 

CH3CH2OH + O2 → 2 CO2 + 3 H2O 

3rd balance the O’s 
You do not want to change the coefficient of CH3CH2OH. So, balance the O’s on the right by changing the coefficient of O2. 
4 O’s + 3 O’s = 7 O’s on right. Make 3 O2’s on left. 

CH3CH2OH + 3 O2 → 2 CO2 + 3 H2O 
Check: 
2 C’s = 2 C’s 
3 + 2 + 1 H’s = 3 * 2 H’s 
1 + (3 * 2) O’s = (2 * 2) + 3 O’s 

If the coefficient of O2 is a fraction, you multiply both sides of the equation by the denominator of the fraction. 
Example: 
C4H10 + O2 → CO2 + H2O 
The coefficient of CO2 is equal to the number of C’s in the reactant = 4 
C4H10 + O2 → 4 CO2 + H2O 
The coefficient of H2O is equal to ½ of the number of H’s in the reactant = 5 
C4H10 + O2 → 4 CO2 + 5 H2O 
Right side has 8 + 5 = 13 O’s. Make 6.5 O2. 
C4H10 + 6.5 O2 → 4 CO2 + 5 H2O 

4th double the entire equation so all coefficients are whole numbers 

2 C4H10 + 13 O2 → 8 CO2 + 10 H2O

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