Analysis of a compound indicates that it contains 1.04 grams k 0.70 g cr and 0.86 g o. find its empirical formula

The empirical formula for the given compound is

Explanation:

We are given:

Mass of Cr = 0.70 g

Mass of K = 1.04 g

Mass of O = 0.86 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Chromium =

Moles of Potassium =

Moles of Oxygen =

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.013 moles.

For Chromium =

For Potassium =

For Oxygen =

Step 3: Taking the mole ratio as their subscripts.

The ratio of K : Cr : O = 2 : 1 : 4

Hence, the empirical formula for the given compound is

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

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