A1.00 l volume of hcl reacted completely with 2.00 l of 1.50 m ca(oh)2 according to the balanced chemical equation below. 2hcl + ca(oh)2 mc013-1.jpg cacl2 + 2h2o what was the molarity of the hcl solution? 0.375 m 1.50 m 3.00 m 6.00 m

The molarity  of the HCl  solution is   6.00M

Calculation

2HCl + Ca(OH)2→ CaCl2 +2H2O

 Step 1:find the   moles of Ca(OH)2

 =  molarity  x volume

=  2l x 1.5 mol/l =  3 .00 moles

Step 2:use the  mole ratio  of HCl : Ca(OH)2 to calculate the moles of HCl

That is Ca(OH)2 :HCl  is 2:1 therefore the moles of HCl= 3.00 moles x2= 6.00 moles.

step 3: find the molarity of HCl

molarity  of HCl = moles of HCL /  volume  in liters of HCl

   = 6.00 moles/ 1  L = 6.00 M

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

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