Amass of 21.5 grams of calcium hydroxide reacts with an excess of phosphoric acid. what mass of calcium phosphate could be recovered from solution?

The balanced equation for the above reaction is as follows;
3Ca(OH)₂ + 2H₃PO₄ ---> Ca₃(PO₄)₂ + 6H₂O
stoichiometry of Ca(OH)₂ to Ca₃(PO₄)₂ is 3:1
Since Ca(OH)₂ is the limiting reactant, amount of Ca₃(PO₄)₂ formed depends on the amount of Ca(OH)₂ present
Number of Ca(OH)₂ reacted - 21.5 g/74 g/mol = 0.29 mol
Therefore number of Ca₃(PO₄)₂ moles formed - 0.29 mol/3 = 0.0967 mol
Mass of Ca₃(PO₄)₂ formed - 0.0967 mol x 310 g/mol = 30.0 g

8.7 degrees celsius and 15.6 degrees fahrenheit

Idon’t know sorry i don’t know the answer i’m s sorry