Calculate the volume of 2.0116 x 10^23 molecules of nh3 gas trapped in a container at a pressure of 2280.0 mmhg and a temperature of 41.000 c

The problem in this question can be solved using the ideal gas formula. Ideal gas formula show interaction between the pressure, volume, temperature and the number of molecules.

n= number of molecule/ avogadro number
n= (2.0116 x 10^23 / 6.02*10^23)= 1/3 mole

T= celcius + 273.15
T= (41+273.15) K=314.15

P=2280 mmHg / (760mmHg/atm)= 3 atm

PV=nRT
V= nrT/ P
V=  1/3 moles * (0.08205 L atm / mol·K)   * 314.15 K / 3 atm
V= 2.864 L

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