Chemistry, 26.07.2019 15:30 CadenSkinner2003

A0.100 l solution of 0.300 m agno3 is combined with a 0.100 l solution of 1.00 m na3po4. calculate the concentration of ag and po43– at equilibrium after the precipitation of ag3po4 (ksp = 8.89 × 10–17).

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Moles of Ag+ = 0.1 L * 0.3 m = 0.03 Moles

moles of PO4-3 = 0.1 L * 1 = 0.1 moles

According to the reaction equation which can be written as:

3Ag + + PO4 3- ↔ Ag3PO4(s)
initial 0.03 0.1
change -3X -X -

Equ (0.03-3X) (0.1-X)

when Ksp = [Ag]^3 [PO43-]

= (0.03-3X)^3 ( 0.1-X)

∴8.89 x 10^-17 = (0.03 - 3X)^3 (0.1-X)

8.89 x 10^-17 = 27 * (X-0.1)^4

∴ X = 2.9 x 10^-6

∴[Ag+] = 0.03 - (3 * (2.9 X 10^-6))

= 0.02998 M

[PO43-] = 0.1 - X = 0.1 - (4.3 x 10^-5)

= 0.0999 M

Answer from: steloiryancy

The concentration of $\bold { Ag^+}$ is 0.02998 M while the concentration of $\bold { PO_4^3^-}$ is 0.0999 M.

The reaction,

$\rm \bold{3Ag ^+ + PO_4^3^- \leftrightarrow Ag_3PO_4(s)}$

At equilibrium,

Concentration of $\bold { Ag^+}$ will be (0.03-3X)

Concentration of $\bold { PO_4^3^-}$ will be ( 0.1-X)

The moles of $\bold { Ag^+}$ is 0.03 Moles

Moles of $\bold { PO_4^3^-}$ is 0.1 moles

Solubility product constant formula,

$\rm \bold{ Ksp = [ Ag^+]^3[ PO_4^3^- ]}$

Put the values in the formula,Solve it for X

$\bold{8.89 x 10^-^1^7 = (0.03 - 3X)^3 (0.1-X)}$

$\bold {X = 2.9\times 10^-^6}$

Put the value of the X, in Ksp formula, we get

$\rm \bold{ [ Ag^+] = 0.02998 M}\\\\\\rm \bold{ [PO_4^3^-] = 0.0999 M }$

Hence we can conclude that the concentration of $\bold { Ag^+}$ is 0.02998 M while the concentration of $\bold { PO_4^3^-}$ is 0.0999 M.

To know more about Ksp, refer to the link:

link

Answer from: Quest

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.

What city is located at 17° south 36° east answers: a)surfer’ town b)white’s beach c)red bank d)

Answer from: Quest

The correct answer is c. orbital shape. "the angular momentum quantum number l describes the shape of an orbital. it corresponds to each orbital type, i.e. (0,1,2,−1)=(s,p,d,f,g,"

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