Given 10.8 grams of substance y, if the substance absorbs 231 kilojoules of energy and the specific heat of the substance is 6.55 j/g·°c, what is the change in temperature?

Answer : The change in temperature will be,

Explanation :

Formula used :

where,

Q = heat absorb = 231 kJ = 231000 J     (1 kJ = 1000 J)

m = mass of substance Y = 10.8 g

c = specific heat of substance =

= change in temperature = ?

Now put all the given value in the above formula, we get:

Therefore, the change in temperature will be,

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