Calculate the energy required to produce 9.00 mol of cl₂o₇ based on the following balanced equation. 2cl₂(g) + 7o₂(g) + 130 kcal → 2cl₂o₇ for 2 mol you need 130 kcal, so how much would you need for 9.00 mol? 9.00 kcal 65 kcal 585 kcal 1,170 kcal

585 kcal .

Explanation:

2Cl₂(g) + 7O₂(g) + 130 kcal → 2Cl₂O₇.

130 kcal are needed to produce 2 mol of Cl₂O₇.

Using cross multiplication:

130 kcal are needed to produce → 2 mol of Cl₂O₇.

??? kcal are needed to produce → 9 mol of Cl₂O₇.

∴ The energy required to produce 9.00 mol of Cl₂O₇ = (130 kcal)(9 mol)/(2 mol) = 585 kcal.

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.