A10g mass of krypton occupies 15.0 l at avpressure of 210 kpa. find the volume

From Boyle's law, we can use the equation
     P1V1 = P2V2
to find the volume when the pressure is increased to 760 kPa:      
     V2 = P1V1 / P2      
     V2 = (210 kPa)(15.0 L) / 760 kPa      
     V2 = 4.14 Liters 
Therefore, the volume is 3.99 Liters after the pressure increased to 760 kPa.  

But if the pressure is increased to 790 kPa, the volume of the krypton will decrease to      
     V2 = P1V1 / P2
     V2 = (210 kPa)(15.0 L) / 790 kPa      
     V2 = 3.99 Liters  

A. 17 hope this dudet