How many moles of acetylene gas occupy a volume of 3.25 l at stp?

0.1449 moles of acetylene gas occupy a volume of 3.25 l at STP .

Explanation:

Using ideal gas equation:

PV = nRT

where,

P = Pressure of acetylene  gas =  (at STP)

V = Volume of acetylene  gas = 3.25 L

n = number of moles of acetylene  gas = ?

R = Gas constant = 0.0821 L.atm/mol.K

T = Temperature of gas = 273.15 K  (at STP)

Putting values in above equation, we get:

n = 0.1449 moles

0.1449 moles of acetylene gas occupy a volume of 3.25 l at STP .

it would be a gas formation