How many moles of ammonium nitrate are in 335 ml?

Data Given:
                  Molarity = 0.425 mol/L
                  Volume = 335 mL
                  Moles   = ?
Solution:
               First of all convert volume from mL into L.
                       
                                  V = 335 / 1000 = 0.335 L
Applying formula of Molarity,
                                   Molarity = moles of solute / Volume of solution
Solving for moles,
                                   Moles = Molarity × Volume
Putting values,
                                   Moles = 0.425 molL⁻¹ ₓ 0.335 L

                                   Moles = 0.142 moles
Results:
Hence, when 0.142 moles of Ammonium nitrate taken and is added with enough water to make a volume of 335 mL, the molarity of the resulting solution will be 0.425 mol/dm³.