45.0 g of ca(no3)2 are used to create a 1.3 m solution. what is the volume of the solution

As we know that Molarity is given as,

                                       M = moles / V 
Solving for V,
                                        V = moles / M (1)
Also, moles is equal to,
                                       moles = mass / M. mass (2)
puting value of moles from eq. 2 into eq. 1,
                                       V = (mass / M.mass) / M
Putting values,
                                       V = (45 g / 164 g/mol) / 1.3 mol/dm³

                                       V = 0.21 dm³ 

Is there a diagram/picture you can provide? it seems this question goes along with a