What is the ph of a buffer solution that is 0.45 m acetic acid (hc2h3o2) and 0.85 m sodium acetate (nac2h3o2)?

According to Henderson–Hasselbalch Equation,
     
                                  pH  =  pKa + log [CH₃COO⁻] / [CH₃COOH]
As,
      Ka of Acetic Acid  =  1.8 × 10⁻⁵

           pKa  = -log Ka
           pKa  = -log 1.8 × 10⁻⁵
           pKa  =  4.74
So,
                                  pH  =  4.74 + log [0.85] / [0.45]

                                  pH  =  4.74 + log 1.88

                                  pH  =  4.74 + 0.276

                                  pH  =  5.01

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