For the reaction, calculate how many grams of the product form when 1.8 g of cao completely reacts. assume that there is more than enough of the other reactant. cao(s)+co2(g)→caco3(s)

Balance Chemical Equation is,

                            CaO ₍s₎  +  CO₂ ₍g₎   →   CaCO₃ ₍s₎

According to Equation

56.07 g of CaO when reacted with excess CO₂ produces  =  100.08 g of CaCO₃.

Then,

    1.8 g of CaO is reacted with excess CO₂  =  X g of CaCO₃ will produce.

Solving for X,
                               X  =  (100.08 g × 1.8 g) ÷ 56. 07 g

                               X  =  3.21 g of CaCO₃

Ithink 2.2 ibs i think i learned a bit about it