Amixture of he and ne at a total pressure of 0.95 atm is found to contain 0.32 mol of he and 0.56 mol of ne. the partial pressure of ne is atm

Answer : The partial pressure of neon gas is, 0.61 atm

Explanation : Given,

Moles of He = 0.32 mol

Moles of Ne = 0.56 mol

Total pressure = 0.95 atm

According to the Raoult's law,

where,

= partial pressure of neon gas

= total pressure of gas

= mole fraction of neon gas

First we have to calculate the moles of fraction of neon gas.

Now we have to calculate the partial pressure of neon gas.

Therefore, the partial pressure of neon gas is, 0.61 atm

the answer is c.the valence of the atoms combine .