How many copper will react with 33.9l of nitrogen stp produce copper nitride

Copper reacts with Nitrogen to produce Copper Nitride

                                    6 Cu  +  N₂   →   2 Cu₃N

At S.T.P

      22.4 L (1mole) of N₂ reacts with  =  381.24 g of Cu to produce Cu₃N

So,

               33.9 L of N₂ will react with  =  X g of Cu

Solving for X,

                              X  = (33.9 L × 381.24 g) ÷ 22.4 L

                              X  =  576.96 g of Cu

As,
                             Moles  =  Mass / M.mass

                             Moles  =  576.96 g / 63.54 g/mol

                             Moles  =  9.08 moles of Cu

Result:
            So, 33.9 L of N₂ will react with 576.96 g (9.08 moles) of Cu.