2ki + pb(no3)2 → 2kno3 + pbi2 determine how many moles of kno3 are created if 0.03 moles of ki are completely consumed.

Hello!

This question can be easily solved using the Mole Ratio of KNO₃/KI in the balanced reaction that is shown below:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

The Mole Ratio of KNO₃/KI in this reaction is 2 moles KNO₃/ 2 moles KI so we can apply the following conversion factor:



So, if 0,03 moles of KI are completely consumed, 0,03 moles of KNO₃ are formed.

Have a nice day!

Ithink 2 is the correct