The chemical equation below shows the combustion of propane (c3h8). c3h8 + 5o2 mc012-1.jpg 3co2 + 4h2o the molar mass of oxygen gas (o2) is 32.00 g/mol. the molar mass of c3h8 is 44.1 g/mol. what mass of o2, in grams, is required to completely react with 0.025 g c3h8? 0.018 0.034 0.045 0.091

   The  mass  of O2   required  to   completely  react  with  0.025g C3H8  is  calculated  as  follows

C3H8  +  5O2 = 3CO2  +  4H2o

 calculate the moles  of  C3H8   that is moles=mass/molar mass
= 0.025g  /  44.1 g/mol=   5.669  x10^-4  moles

by  use of  mole  ratio from  reacting  equation   between  C3H8  to  O2  which is  1:5 the  moles  of  O2 =  5  x  (5.669  x10^-4)  =  2.83  x10^-3  moles

mass  of  O2  =  moles  x  molar  mass
=  (2.83  x10^-3)moles  x  32 g/mol  =  0.091   g ( answer  D)