When entering coefficients to balance equations, recall that just writing the symbol implies "1." therefore, if a coefficient of "1" is required, choose "blank" for that box. balance the following equation. 2c2h2 + o2→ 4co2 + h2o

The Equation given in statement is as follow,

                              2 C₂H₂  +  O₂     →    4 CO₂  +  H₂O

According to equation,

Carbon atoms on reactant side are 4 in number, and that on product side are also 4 in number. SO, carbon atoms are balanced.

Hydrogen atoms on reactant side are 4, and on product side are 2. Means Hydrogen atoms are not balance. So, to balance them multiply H₂O with 2. So,
                              2 C₂H₂  +  O₂     →    4 CO₂  +  2 H₂O

Now, calculate number of Oxygen atoms on both sides. There are 2 Oxygen atoms on reactant side and 10 Oxygen atoms on product side. So, to balance them multiply O₂ on reactant side with 5. So,

                              2 C₂H₂  +  5 O₂     →    4 CO₂  +  2 H₂O

Above Equation is balanced.

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.