What is the pressure of 0.5 mol nitrogen (n2) gas in a 5.0 l container at 203 k?

The pressure of the nitrogen in the container is 168.774 kPa

Explanation:

The volume, pressure, temperature and mol of a gas are linked through the ideal gas law which is:

p . V = n . R . T

Where p is the pressure of the gas, V the volume of the gas, n the amount of moles of the gas, T the temperature of the gas and R the universal gas constant.

The universal gas constant R we will be using is:

For example, What is the temperature of 4 mol of gas in a 10 Liters container at 300kPa?

The data is:

V = 10L

p = 300kPa

n = 4 moles

T = ?

Now we put the data in the equation and calculate the temperature.

10L ⋅ 300kPa = 4mol ⋅ ⋅ T

T = 10L· 300kPa÷4mol ⋅

T= 90.21 K

So,  knowing all the data except one, using the ideal gas law we can calculate it.

The equation for this case would be:

p = 0.5mol · · 203K ÷ 5.0L

And the result:

p = 168.774 kPa

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