Which volume of 0.10 m naoh(aq) exactly neutralizes 1.50 milliliters of 0.20 m hbo3(aq)?

From the information given above, NAOH is a base and HNO3 is an acid.
The chemical equation for the reaction is as follows"
NAOH + HNO3 = NANO3 + H2O
From these equation, we can see that the mole ratio of acid to base is 1:1.
In the question, we are given the following information:
Concentration of the acid, CA = 0.20 M
Volume of the acid, VA = 15 ML
Concentration of the base, CB = 0.10 M
 We are to calculate the volume of the base, VB = ?
The formula for calculating volume and concentration for acid and base is as follows:
CA * VA = CB * VB
VB = CA * VA / CB = 0.20 * 15 / 0.1 = 3.0 / 0.1 = 30
VB = 30 ML.
Therefore, the volume of base required to neutralize the acid is 30 ml.

Idon't know hope someone you