Oct-1-yne (hc≡cch2ch2ch2ch2ch2ch3) reacts rapidly with nah, forming a gas that bubbles out of the reaction mixture, as one product. oct-1-yne also reacts rapidly with ch3mgbr, and a different gas is produced. write balanced equations for both reactions and identify the gases formed.

As we know that terminal Alkyne (alkyne with triple bond at the end) are acidic in nature, they can donate proton. When Sodium Hydride is reacted with 1-Octyne , the hydride abstract the terminal proton and forms Hydrogen Gas, while Methyl Magnesium Bromide when reacted with 1-Octyne eliminates Methane gas. Both reactions are given below,

Result:
          Gas evolved in reaction of NaH is H₂.

          Gas evolved in reaction of CH₃MgBr is CH₄.

- Addition of NaH releases hydrogen gas.

- Addition of releases methane.

Explanation:

Hello,

On the attached picture, you will find both reactions as shown below:

- Addition of NaH: in this case, due to the fact that the alkynes are slightly acid, they are able to donate one proton, thus, the hydrogen bonded with the triple-bonded carbon will be released as hydrogen gas.

- Addition of : in this case, a Grignard reactant, magnesium methyl bromide, is added so the methyl from such reactant will accept the hydrogen bonded with the triple-bonded carbon, forming a grignard intermediate and methane gas.

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D. is the answer hope that you

The answer is celsius