If you want to conduct an electrical current, which situation would produce a solution capable of this? a. dissolving water in oil. b. dissolving sugar in water. c. dissolving solid nabr in oil. d. dissolving solid naf in water.

Option (d) is the correct answer.

Explanation:

When we dissolve an ionic compound in water then it readily dissociates into ions.

This is because ionic compounds are polar in nature and like dissolves like. Since, water is also polar in nature hence,

For example, NaF is an ionic compound as it is formed by transfer of an electron from sodium atom to fluorine atom.

So, when NaF is dissolved in water then it dissociates into and ions.

As electric current occurs due to movement of electrons or ions. Therefore, a solution with and ions is able to conduct electricity.

Thus, we can conclude that if you want to conduct an electrical current, then dissolving solid NaF in water would produce a solution capable of this.

water is used to store them because it would keep the radiation from getting out in the open and causing harm to the workers

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol