The half-life of phosphorus-32 is 14.26 days. calculate its decay constant. express the decay constant numerically in inverse days.

The decay constant(λ) = 0.0486/day

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.

Usually radioactive elements have an unstable atomic nucleus.

The main particles are emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles

General formulas used in decay:

T = duration of decay

t 1/2 = half-life

N₀ = the number of initial radioactive atoms

Nt = the number of radioactive atoms left after decaying during T time

The half-life can be expressed in a decay constant( λ)

The half-life of phosphorus-32 is 14.26 days

Then : t 1/2 = 14.26 days

The identity of the missing nucleus

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the process of radioactive decay

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nuclear fusion and nuclear fission reactions

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the product of radioactive decay

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the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3