The solubility of manganese (ii) hydroxide (mn(oh)2) is 2.2 x 10-5 m. what is the ksp of mn(oh)2?

-When Ksp is the solubility product constant for a solid substance when it

dissolved in an aqueous solution, and measure the level at which a solute

dissolves in the solution.

- and we have the solubility and it is the maximum quantity of solute which can dissolve in a certain solute 

we can assume the solubility = X = 2.2 x 10^-5 M

and when the balanced reaction equation is:

Mn(OH)2(s)  ↔ Mn2+   +  2OH-

∴ the Ksp expression is = [Mn2+] [OH-]^2

when [Mn2+] = X = 2.2 x 10^-5 M

and [OH-] = 2X = 2*(2.2 x 10^-5) = 4.4 x 10^-5 M

by substitution:

∴ Ksp = X * (2X)^2

           = (2.2 x 10^-5)(4.4 x 10^-5)^2

           = 4.3 x 10^-14

Answerit curves up and levels out.explanationwe assume that the container contains absolutely no ammonia to begin with as it states that "nitrogen gas and hydrogen gas" react to "produce ammonia."at dynamic equilibrium, the product and reactant concentrations are equal.this means that, starting from a concentration of zero, [nh₃] must curve "up" from zero and then level out to a constant concentration.

Answerhave membrane-bound organelles;