Answers: 1
![-log [H^{+}]](/tpl/images/0123/3207/822be.png)
![[H^{+}] = 1 \times 10^{-3}](/tpl/images/0123/3207/7e0f1.png)
M
, ![[H^{+}]](/tpl/images/0123/3207/85507.png)
and HA is as follows.![K_{a} = \frac{[H^{+}][A^{-}]}{[HA]}](/tpl/images/0123/3207/04688.png)
of given acid is 5.0.
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