How many moles of carbon dioxide are produced with using 5.80 grams of acetylene?

Acetylene on combustion produces CO₂ and H₂O,

                             C₂H₂  +  7/2 O₂    →     2 CO₂  +  3 H₂O

According to Balance equation,

                       28.05 g of C₂H₂ produces  =  2 moles of CO₂
So,
                     5.80 g of C₂H₂ will produce  =  X moles of CO₂

Solving for X,
                                 X  =  (5.80 g × 2 mol) ÷ 28.05 g

                                 X  =  0.41 Moles of CO₂

Variables,control,conclusion and finally scientific theory