An electric current is applied to a 1.0 m nai solution. (i) write the balanced oxidation half reaction for the reaction that takes place. (ii) write the balanced reduction half-reaction for the reaction that takes place. (iii) which reaction takes place at the anode, the oxidation

Answers are:
1) The balanced oxidation half reaction: 2I⁻(aq) → I₂(s) + 2e⁻.
Iodine is oxidized (lost electrons) from -1 to neutral charge (0).
2) The balanced reduction half-reaction: 2H₂O(l) + 2e⁻ → H₂(g) + 2OH⁻.
Hydrogen is reduced (gain electrons) from +1 to neutral charge.
3) The oxidation reaction takes place at the anode.

It conforms what ever surface its in.