Explain how you would prepare a solution of sucrose with a molarity of 0.25.

Solution of 0.25 M is prepared in two steps,

1) Calculate Amount of Solute:

                                Molar Mass of Solute:  342.3 g/mol

As we know,
                            Molarity  =  Moles / 1 dm³
or,
                            Moles     =  Molarity × 1 dm³
Putting Values,
                            Moles     =  0.25 mol.dm⁻³ × 1 dm³

                            Moles     =  0.25 moles

Now, find out mass of sucrose,
As,               
                            Moles      =   Mass / M.mass
or,
                            Mass       =  Moles × M.mass
Putting Values,
                            Mass       =  0.25 mol × 342.3 g.mol⁻¹

                            Mass       =  85.57 g

2) Prepare Solution:
                               Take Volumetric flask and add 85.57 g of sucrose in it. Then add distilled water up to the mark of 1 dm³. Shake well! The solution prepared is 0.25 M in 1 Liter.

U whay do you need with?

We first assume that this gas is an ideal gas where it follows the ideal gas equation. the said equation is expressed as: pv = nrt. from this equation, we can predict the changes in the pressure, volume and temperature. if the volume and the temperature of this gas is doubled, then the pressure still stays the same.