Calculate the ph of a buffer that is 0.158 m hclo and 0.099 m naclo. the ka for hclo is 2.9 × 10-8

pH is calculated using Handerson- Hasselbalch Equation,

                             pH  =  pKa  +  log [Conjugate Base] / [Acid]  --- (1)

Conjugate Base  =  NaClO

Acid                    =  HClO

So,

                                      pH  =  pKa  +  log [NaClO] / [HClO]

We are having concentration of acid and salt but missing with pKa,

pKa is calculated as,

                                     pKa  =  -log Ka

Putting value of Ka,

                                     pKa  =  -log 2.9 × 10⁻⁸

                                     pKa  =  7.53

Now,

Putting all values in eq. 1,

                                     pH  =  7.53 + log [0.099] / [0.158]

                                     pH  =  7.326

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