Asample of an unknown substance has a mass of 0.158 kg. if 2,510.0 j of heat is required to heat the substance from 32.0°c to 61.0°c, what is the specific heat of the substance? use mc029-1.jpg.

The specific  heat of the substance  is  0.548  J/g/c

calculation

 Specific heat is calculated  using  Q=MCΔT  formula, where;

Q(heat)=  2510.0 j

 M (mass)=  0.158  kg  convert into  g

   = 1 Kg = 1000 g

     0.158 kg= ? g

      = (0.158 kg  x  1000g)  / 1  kg = 158  g

C(  specific heat capacity) = ?

ΔT(change in temperature)  = 61.0 -32c   = 29 c

   make  C  the subject of the  formula  by dividing both side by m andΔT

  c=  Q /mΔT

 C=  [2510.0 j  /    158 g x 29]  = 0.548  j/g/c

out of these options:

ability to burn paper

pure sodium reacting violently with water

the boiling point of water

helium does not tend to react with anything

i would say this is a physical property:

helium does not tend to react with anything

why? :

i said helium does not tend to react with anything because well, it reacts to ! but ability to burn paper, pure sodium reacting violently with water, & the boiling point of water are chemical or

physical properties: the properties of a substance that can be observed without changing the chemical makeup of the substance

chemical properties: properties of a substance relating to the chemical nature and reactivity of the substance

let that person have a turn to speak : )