Here is the discharge reaction for an alkaline battery: zn(s) + 2mno2(s) + h2o(l)\longrightarrow⟶⟶zn(oh)2(s) + mn2o3(s) which species is reduced as the battery is discharged?

Explanation:

the reaction is  

Zn(s) + 2MnO₂(s) + H₂O(l) ⟶ Zn(OH)₂(s) + Mn₂O₃(s)

This is the discharge reaction, where Zn is undergoing oxidation and Mn is undergoing reduction.

The anode reaction is:

The cathode reaction is:

Thus here MnO₂  is undergoing reduction (and the element undergoing reduction is Mn).

the correct answer is boyle

its mg hope this